a riddle

Here’s a riddle.

Let’s say your goal is a hamburger, fries, and coleslaw for the best
value possible.

Here are the facts:
A hamburger is 139 baht, and includes one side.
A gourmet hamburger is 189 baht, and includes one side.
Coleslaw as a side is 30 baht.
Fries as a side is 60 baht.
Fries ordered as a size are roughly twice as big as the “included” side
size with both hamburgers.

My solution to the riddle is:
2 x hamburgers @ 139 baht each, one with coleslaw, one with fries. Keep
the second hamburger for the next meal.
Total cost: 278 baht.

Alternative solution:
1 x gourmet hamburger @ 189 baht, with fries. Add one side of coleslaw.
Total cost: 219 baht.

The pro of the first solution is that you get a second hamburger for a
future meal. The con is that they aren’t delicious gourmet hamburgers.
The pro/con of the second solution is the opposite.

Poor solution:
1 x gourmet hamburger @ 189 baht, with coleslaw. Add one side of fries.
Total cost: 249 baht.
I think you’d really need to like fries for this to be a good solution.

Worst solution:
2 x gourmet hamburgers @ 189 baht, one with coleslaw, one with fries.
Keep the second hamburger for the next meal.
Total cost: 378 baht.
The biggest failing of this idea is that the gourmet hamburgers wouldn’t
keep as well on account of their gourmet-ish ingredients.

Discuss.

• 

  By Burger Patty, February 26, 2009 @ 1:57 am

  None can´t keep one burger for the next meal. I bet you will eat both.

• 

  By Burger Patty, February 26, 2009 @ 1:59 am

  Cheapest solution:

  A hamburger is 139 baht with fries.
  + Coleslaw as a side is 30 baht.
  = 169 baht

• 

  By Chuckler, February 26, 2009 @ 3:02 pm

  Ah yes, but is it the best value solution? Cheapest and value do not neccessarily correlate.

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